Problem Formulation
Given a string in the octal form:
s = '0o77'
# or s = '77'
How to convert the octal string to an integer in Python?
For example, you want to convert the octal string 'o10' to the decimal integer 8.
Here are a few other examples:
| Octal String | Decimal |
|---|---|
'0o0' |
0 |
'0o4' |
4 |
'0o10' |
8 |
'0o14' |
12 |
'0o20' |
16 |
'0o77' |
63 |
'0o77777' |
32767 |
Oct String to Integer using int() with Base 8
To convert an octal string to an integer, pass the string as a first argument into Python’s built-in int() function. Use base=8 as a second argument of the int() function to specify that the given string is an octal number. The int() function will then convert the octal string to an integer with base 10 and return the result.
Here’s a minimal example:
>>> int('0o77', base=8)
63
Examples
And here’s how you can convert the additional examples shown above:
>>> int('0o0', base=8)
0
>>> int('0o4', base=8)
4
>>> int('0o10', base=8)
8
>>> int('0o14', base=8)
12
>>> int('0o20', base=8)
16
>>> int('0o77', base=8)
63
>>> int('0o77777', base=8)
32767
You actually don’t need to use the prefix '0o' because your second argument already defines unambiguously that the given string is an octal number:
>>> int('0', base=8)
0
>>> int('4', base=8)
4
>>> int('10', base=8)
8
>>> int('14', base=8)
12
>>> int('20', base=8)
16
>>> int('77', base=8)
63
>>> int('77777', base=8)
32767
However, skipping the base but leaving the prefix raises a ValueError: invalid literal for int() with base 10: '0o77':
>>> int('0o77')
Traceback (most recent call last): File "<pyshell#16>", line 1, in <module> int('0o77')
ValueError: invalid literal for int() with base 10: '0o77'
It assumes that the input string is in base 10 when in fact, it isn’t.
Note: Even though passing a prefixed string '0o...' into the int() function is unambiguous, Python’s int() function doesn’t accept it if you don’t also define the base. This may be fixed in future versions!
In fact, you can specify the base argument as 0 to switch on base guessing—which should be the default behavior anyway! 
Base Guessing
You can pass a prefixed string '0o...' into the int() function and set the base to 0 to switch on base guessing in Python. This uses the prefix to determine the base automatically—without you needing to set it to 16. Yet, you still have to set it to 0 so the benefit is marginal in practice.
>>> int('0o7', base=8)
7
>>> int('0o7', base=0)
7
>>> int('0o7', 0)
7
Converting Octal Literals to Int
If you don’t have an octal string but a octal number—called a literal—such as 0xff, you don’t even need the int() function because Python will automatically convert it to a decimal number:
>>> 0o743
483
>>> 0o7
7
>>> 0o10
8
Background int()
Syntax: int(value [, base]) – > int
| Argument | value |
A Python object to be converted into an integer number. The value object must have an __int__() method that returns the associated integer number—otherwise a TypeError will be raised. |
base |
An optional integer argument base to define the base of the numerical system in the value argument. If you set the base, the value argument must be a string. The base argument determines how the string argument is interpreted. |
|
| Return Value | int |
Returns an integer number after converting the input argument value using its required __int__() method for the conversion. |
Do you still need more background information about Python’s built-in int() function? No problem, read over the related tutorial.
Related Tutorial: Python’s Built-in int() Function
https://www.sickgaming.net/blog/2022/12/...in-python/