Posted by: xSicKxBot - 10-17-2022, 03:24 AM - Forum: Lounge
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Call Of Duty Mobile: Zombies Shi No Numa Secret Boss Fight Guide
The latest season has arrived to Call of Duty Mobile, and as the title suggests, Season 9: Zombies Are Back is an update focused on the undead. The Halloween-themed update also brings the return of the classic Shi No Numa Zombies map, which features a hidden boss fight. Here is everything you need to know to unlock the option to complete the Easter egg steps and defeat the boss.
How to unlock Shi No Numa's Easter egg boss
Shi No Numa was briefly featured in Call of Duty Mobile back in 2019, but the classic Zombies map was removed and eventually replaced with the objective-style "Undead Siege" mode. Even if you played Shi No Numa the first time it was introduced into the mobile game, you'll still need to go through these steps to unlock the mode needed to complete the boss fight.
When you first log onto the game and download the Season 9 update, you'll need to do two things in order to unlock the ability to access the mode needed for the Easter egg.
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Once the site of fierce territorial battles, it has since developed into one of the continent's leading trade and financial centers.
However, pressure from the Erebonian Empire and the Calvard Republic is steadily increasing. While corrupt officials from both sides remain locked in political disputes, the mafia and underground criminal organizations are preparing to start a war.
In the midst of all this chaos, the Crossbell Police Department has lost the trust of its people.
Among them are Lloyd Bannings, a rookie agent,
Elie MacDowell, granddaughter of Crossbell's mayor,
Tio Plato, a young sorcereress who wields an orbal staff,
and Randy Orlando, a former security guard.
The foursome are assigned to a new department, the Special Support Section, where they are left with no choice but to join forces in the face of adversity.
This is a story about four unlikely heroes fighting to overcome the walls defining their way of life.
The release date is proposed for September 21, 2017 and it’s time to make sure your code will work with JDK 9. As you probably know, you will still be able to use the classpath and code with any official Java SE APIs and supported JDK-specific APIs. You will run into problems if your code uses certa...
Posted by: xSicKxBot - 10-16-2022, 03:49 AM - Forum: Python
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Python – Return NumPy Array From Function
5/5 – (1 vote)
Do you need to create a function that returns a NumPy array but you don’t know how? No worries, in sixty seconds, you’ll know! Go!
A Python function can return any object such as a NumPy Array. To return an array, first create the array object within the function body, assign it to a variable arr, and return it to the caller of the function using the keyword operation “return arr“.
For example, the following code creates a function create_array() of numbers 0, 1, 2, …, 9 using the np.arange() function and returns the array to the caller of the function:
import numpy as np def create_array(): ''' Function to return array ''' return np.arange(10) numbers = create_array()
print(numbers)
# [0 1 2 3 4 5 6 7 8 9]
The np.arange([start,] stop[, step]) function creates a new NumPy array with evenly-spaced integers between start (inclusive) and stop (exclusive).
The step size defines the difference between subsequent values. For example, np.arange(1, 6, 2) creates the NumPy array [1, 3, 5].
To better understand the function, have a look at this video:
I also created this figure to demonstrate how NumPy’s arange() function works on three examples:
In the code example, we used np.arange(10) with default start=0 and step=1 only specifying the stop=10 argument.
If you need an even deeper understanding, I’d recommend you check out our full guide on the Finxter blog.
You can also create a 2D (or multi-dimensional) array in a Python function by first creating a 2D or (xD) nested list and converting the nested list to a NumPy array by passing it into the np.array() function.
The following code snippet uses nested list comprehension to create a 2D NumPy array following a more complicated creation pattern:
import numpy as np def create_array(a,b): ''' Function to return array ''' lst = [[(i+j)**2 for i in range(a)] for j in range(b)] return np.array(lst) arr = create_array(4,3)
print(arr)
Output:
[[ 0 1 4 9] [ 1 4 9 16] [ 4 9 16 25]]
I definitely recommend reading the following tutorial to understand nested list comprehension in Python:
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Posted by: xSicKxBot - 10-15-2022, 08:22 AM - Forum: Python
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Can a Python Dictionary Have a List as a Value?
5/5 – (1 vote)
Question
Question: Can you use lists as values of a dictionary in Python?
This short article will answer your question. So, let’s get started right away with the answer:
Answer
You can use Python lists as dictionary values. In fact, you can use arbitrary Python objects as dictionary values and all hashable objects as dictionary keys. You can define a list [1, 2] as a dict value either with dict[key] = [1, 2] or with d = {key: [1, 2]}.
Here’s a concrete example showing how to create a dictionary friends where each dictionary value is in fact a list of friends:
You cannot use lists as dictionary keys because lists are mutable and therefore not hashable. As dictionaries are built on hash tables, all keys must be hashable or Python raises an error message.
Here’s an example:
d = dict()
my_list = [1, 2, 3]
d[my_list] = 'abc'
This leads to the following error message:
Traceback (most recent call last): File "C:\Users\xcent\Desktop\code.py", line 3, in <module> d[my_list] = 'abc'
TypeError: unhashable type: 'list'
To fix this, convert the list to a Python tuple and use the Python tuple as a dictionary key. Python tuples are immutable and hashable and, therefore, can be used as set elements or dictionary keys.
Here’s the same example after converting the list to a tuple—it works!
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